CODEWITHSUNDEEP
batch-file
Anand
Anand

Reputation: 2359

How to write call command in batch file conditionally?

I have two lines of call command in batch file like this:

call execute.cmd
call launch.cmd

My need is to call the launch.cmd if and only if call to execute.cmd succeeds. So is there any way by which can I put some condition here?

execute.cmd does not return any value here.

Upvotes: 5

Views: 4684

Answers (2)

jhclark
jhclark

Reputation: 2563

I believe this is a duplicate of How do I make a batch file terminate upon encountering an error?.

Your solution here would be:

call execute.cmd
if %errorlevel% neq 0 exit /b %errorlevel%
call launch.cmd
if %errorlevel% neq 0 exit /b %errorlevel%

Unfortunately, it looks like Windows batch files have no equivalent of UNIX bash's set -e and set -o pipefail. If you're willing to abandon the very limited batch file language, you could try Windows PowerShell.

Upvotes: 3

Ioan Paul Pirau
Ioan Paul Pirau

Reputation: 2833

If execute.cmd returns an integer than you can use a IF command to check it's return value and if it matches the desired one than you can call launch.cmd

Suppose that execute.cmd returns 0 if it is successful or an integer >= 1 otherwise. The batch would look like this:

rem call the execute command
call execute.cmd
rem check the return value (referred here as errorlevel)
if %ERRORLEVEL% ==1 GOTO noexecute
rem call the launch command
call launch.cmd

:noexecute
rem since we got here, launch is no longer going to be executed

note that the rem command is used for comments.

HTH,
JP

Upvotes: 5

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