Reputation: 11
If a power meter measures 1% of the total channel power to be -33.9dBm, what is the total channel power?
Upvotes: -2
Views: 37
Reputation:
The key concept here is that dBs enable the use of addition vs. multiplication:
Pt[in Watts] = 100 * Pm[in Watts] ==>
Pt[in dBm's] = 10 log10(100) + Pm[in dBm's] =
20 + -33.9 =
-13.9dBm
Check:
Pm = (10^(-33.9dBm/10))*0.001 = 0.000000407380278 Watts
Pt = (10^(-13.9dBm/10))*0.001 = 0.00004073802778 Watts
Pt[in milliWatts] = 100 * Pm[in milliWatts] =
0.00004073802778 =? 100 * 0.000000407380278 =
0.0000407380278
Upvotes: 0