CODEWITHSUNDEEP
pythonregexmatch
PParker
PParker

Reputation: 1511

Optimize a regex for German mobile numbers

I have a Regex which extracts German mobile phone numbers from a website:

[^\d]((\+49|0049|0)1[567]\d{1,2}([ \-/]*\d){7})(?!\d)

As you can see in the demo it works quite well. The only pattern which doesn't match yet is:

+49 915175461907

Please see more examples in the linked demo. The problem is the whitespace behind +49.

How do I need to change the current regex pattern in order to match even these kind of patterns?

Upvotes: 3

Views: 378

Answers (3)

KZiovas
KZiovas

Reputation: 4749

Add an optional white space:

[^\d]((\+49|0049|0)\s?(1|9)[1567]\d{1,2}([ \-/]*\d){7,8})(?!\d)

Update-Capturing beginning of line

If you want is to match numbers without them necessarily starting with a line break you can use this. It matches anything except digits before phone number:

 (^|[^\d])((\+49|0049|0)\s?(1|9)[1567]\d{1,2}([ \-/]*\d){7,8})(?!\d)

test it here

Upvotes: 1

anubhava
anubhava

Reputation: 785651

A better regex would be:

(?<!\d)(?:\+49|0049|0) *[19][1567]\d{1,2}(?:[ /-]*\d){7,8}(?!\d)

Updated RegEx Demo

Changes:

  • (?<!\d): Make sure previous character is not a digit
  • [19][1567]: Match 1 or 9 followed by one of the [1567] digit
  • {7,8}: Match 7 or 8 repetitions of given construct
  • Better to keep an unescaped hyphen at first or last position in a character class
  • Avoid capturing text that you don't need by using non-capture group

Upvotes: 5

Mayot
Mayot

Reputation: 79

No brain method : removing space before regex.

Otherwise matching non withe space in regex is \s so (maybe too much parenthesis)

[^\d](((\+49|0049|0)([\s]{0,1})1)[567]\d{1,2}([ \-/]*\d){7})(?!\d)

Upvotes: 3

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