Reputation: 445
String1: {{word1|word2|word3 (word4 word5)|word6}}
String2: {{word1|word2|word3|word6}}
With this regex sentence:
(?<=\{\{)(\w+(?:\s+\w+)*)\|(\w+(?:\s+\w+)*)\|(\w+(?:\s+\w+)*)\|(\w+(?:\s+\w+)*)(?=\}\})
I capture String2 as groups. How can I change the regex sentence to capture (word4 word5)
also as a group?
Upvotes: 2
Views: 842
Reputation: 110685
You could simplify the expression by matching the desired substrings rather than capturing them. For that you could use the following regular expression.
(?<=[{| ])\w+(?=[}| ])|\([\w ]+\)
Regex demo <¯\(ツ)/¯> Python demo
The elements of the expression are as follows.
(?<= # begin a positive lookbehind
[{| ] # match one of the indicated characters
) # end the positive lookbehind
\w+ # match one or more word characters
(?= # begin a positive lookahead
[}| ] # match one of the indicated characters
) # end positive lookahead
| # or
\( # match character
[\w ]+ # match one or more of the indicated characters
\) # match character
Note that this does not validate the format of the string.
Upvotes: 1
Reputation: 626870
You can add a (?:\s*(\([^()]*\)))?
subpattern:
(?<=\{\{)(\w+(?:\s+\w+)*)\|(\w+(?:\s+\w+)*)\|(\w+(?:\s+\w+)*)(?:\s*(\([^()]*\)))?\|(\w+(?:\s+\w+)*)(?=\}\})
See the regex demo.
The (?:\s*(\([^()]*\)))?
part is an optional non-capturing group that matches one or zero occurrences of
\s*
- zero or more whitespaces(
- start of a capturing group:
\(
- a (
char[^()]*
- zero or more chars other than (
and )
\)
- a )
char)
- end of the group.If you need to make sure only whitespace separated words are allowed inside parentheses, replace [^()]*
with \w+(?:\s+\w+)*
and insert (?:\s*(\(\w+(?:\s+\w+)*\)))?
:
(?<=\{\{)(\w+(?:\s+\w+)*)\|(\w+(?:\s+\w+)*)\|(\w+(?:\s+\w+)*)(?:\s*(\(\w+(?:\s+\w+)*\)))?\|(\w+(?:\s+\w+)*)(?=\}\})
See this regex demo.
Upvotes: 1