CODEWITHSUNDEEP
python
Vic
Vic

Reputation: 37

Finding all combinations of a list of numbers without the pair being the same in python

I would like to find all combinations of my list of numbers without the pair being the same. The code I've written below gives me all combinations. So, I also get [1, 1], [2, 2] and [3, 3], which I'd like to remove.

nr_list = [1, 2, 3]
combinations = []
for a in nr_list:
    for b in nr_list:
        pair = [a, b]
        combinations.append(pair)
print(combinations)

Upvotes: 0

Views: 286

Answers (3)

andrey.s
andrey.s

Reputation: 121

from itertools import permutations

nr_list = [1, 2, 3]
print(list(permutations(nr_list, 2)))
# [(1, 2), (1, 3), (2, 1), (2, 3), (3, 1), (3, 2)]

Similar question: link

Upvotes: 2

hopperelec
hopperelec

Reputation: 133

Just don't append the pair to the combinations if the items in pair are equal ie if pair[0] != pair[1]:

Upvotes: 1

Akash Kumar
Akash Kumar

Reputation: 327

Try this code

nr_list = [1, 2, 3]
combinations = []
for a in nr_list:
    for b in nr_list:
        if(a!=b):
            pair = [a, b]
            combinations.append(pair)
print(combinations)

Upvotes: 0

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