CODEWITHSUNDEEP
python
An613
An613

Reputation: 9

How can I make my calculator code repeat without asking the user to input anything? - continuous calculation in Python

def calculation():

    num1 = float(input())
    num2 = float(input())
    op = input()

    if op == "+":    #code for addition
        print(num1 + num2)

    elif op == "-": #code for subtraction
        print(num1 - num2)

    elif op == "/": #code for division
        print(num1 / num2)

    elif op == "*": #code for multiplication
        print(num1 * num2)

    #elif ZeroDivisionError:
        #print("Divided by zero")

    else: #code if invalid operator is entered
        print("Invalid operator entered")


calculation() #calling the fucntion

Right now the code only runs when I call the function. Id like it to run non-stop, like a physical calculator. I am also trying to sort out how to not break the code if division by 0 occurs. Thank you for any help.

Upvotes: 0

Views: 600

Answers (2)

user2390182
user2390182

Reputation: 73460

A simple infinite loop will do:

while True:
    calculation()

You can also shorten your calculation function, mapping your symbols to the appropriate operator functions and handling exceptions as they occur:

from operator import add, sub, mul, truediv

ops = {"+": add, "-": sub, "*": mul, "/": truediv}

def calculation():
    num1 = float(input())
    num2 = float(input())
    op = input()

    try:
        print(ops[op](num1, num2))
    except KeyError:
        print("Invalid operator entered")
    except ZeroDivisionError:
        print("Divided by zero")

Upvotes: 1

roman_ka
roman_ka

Reputation: 578

I believe the default way is to use while True:


while True:
    # your code here

True is by default True, so your program will run until it is manually terminated.

As with the division by zero, you can do


...
elif op == "/": #code for division
    if num2 == 0:
        print('Cannot divide by zero!')
    else:
        print(num1 / num2)

Upvotes: 1

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