CODEWITHSUNDEEP
pythonlist
Patrick_Chong
Patrick_Chong

Reputation: 534

How to choose the minimum value in one array that does not appear in the other using one line?

nearest_distance_table = [1,4,5,9,10,14,15]
nodes_explored = [2,10,14]

I want to assign a variable next to the minimum value of nearest_distance_table that is NOT in nodes_explored. Is there a one-liner using min() to do this? I know how to do this using a for loop, but is there a way to do it with one line with min()?

Using a for-loop:

minimum = float("inf")
for I in nearest_distance_table: 
    if I < minimum and I not in nodes_explored: 
        minimum = I
print(I)

Upvotes: 0

Views: 37

Answers (2)

Kemp
Kemp

Reputation: 3649

You can convert the lists to sets:

lowest = min(set(nearest_distance_table).difference(nodes_explored))

Note that this will not work if you want to preserve duplicate values. For example,

nearest_distance_table = [2, 2, 4]
nodes_explored = [2]

will give 4 as the answer as the two 2s will be collapsed into a single value and then removed. This is the same behaviour as in your example.

Upvotes: 0

Daweo
Daweo

Reputation: 36680

You might use comprehension as follows

nearest_distance_table = [1,4,5,9,10,14,15]
nodes_explored = [2,10,14]
minimum = min(i for i in nearest_distance_table if i not in nodes_explored)
print(minimum)

output

1

Upvotes: 1

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