CODEWITHSUNDEEP
javascriptscope
temuri
temuri

Reputation: 2807

Is variable updated "by reference"?

I have the following simple script.

<script>
SPC = {
    a : [10],
    b : 10,

    t: function()
    {
        y = this.a;
        z = this.b;
        y[0]++;
        z++;
        alert('this.a[0] = ' + this.a[0] + '\nthis.b = ' + this.b)
    }
}

SPC.t();
SPC.t();
</script>

Running it in your browser will display two alert boxes with:

this.a[0] = 11 this.b = 10

and

this.a[0] = 12 this.b = 10

The question is, why does the value of this.a[0] increment? I'm assigning "y = this.a" and updating element of "y" as "y[0]++;"?

At the same time, exactly the same thing is happening with "b": "z = this.b; z++". Yet, "this.b" remains equal to 10.

How can I change value of "y[0]" in the local scope without affecting "this.a"?

Any ideas?

Thanks!

Upvotes: 3

Views: 160

Answers (3)

lc.
lc.

Reputation: 116498

a is an array, and you're simply copying a reference to the array into y. You need to copy the array a's contents into a new array y instead (using Array.slice() (y = a.slice() in your case) is the easiest way).

(Or, if you only need a[0], you can set y = a[0]. Subsequent changes to y will not affect a[0], since you are copying the value.)

See the "Javascript Arrays Are Assigned By Reference" and "Passing Arrays As Values" sections of this article for more information.

Upvotes: 7

Rorick
Rorick

Reputation: 8953

Try Array.slice() function.

y = this.a.slice()

This will create a copy of a array and assign it to y. So modification of y won't affect a.

Upvotes: 2

Syed Tayyab Ali
Syed Tayyab Ali

Reputation: 3681

you are assigning the address value of array a and b into y and z. therefore, y, and z become the exact copy of a and b. instead of assigning address value into y and z. you just need to take content value of a and b and assign them into y and z y = a[0]

z = b[0]

and then y++

Upvotes: 0

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