CODEWITHSUNDEEP
pythonclassintrospection
Staale
Staale

Reputation: 28008

How do I get the filepath for a class in Python?

Given a class C in Python, how can I determine which file the class was defined in? I need something that can work from either the class C, or from an instance of C.

I am doing this because I am generally a fan of putting files that belong together in the same folder. I want to create a class that uses a Django template to render itself as HTML. The base implementation should infer the filename for the template based on the filename that the class is defined in.

Say I put a class LocationArtifact in the file "base/artifacts.py", then I want the default behaviour to be that the template name is "base/LocationArtifact.html".

Upvotes: 140

Views: 85089

Answers (4)

mustapha_1234
mustapha_1234

Reputation: 49

You can use the error to get the path of your class

import os
import traceback
class C:
  def getClassPath(self):
    #get foldet path
    try:
        raise ValueError("Example error")
    except Exception as e:
        tb = traceback.extract_tb(e.__traceback__)
       
        return os.path.dirname(tb[-1].filename)
c = C()
print('path is',c.getClassPath())

Upvotes: -1

DNS
DNS

Reputation: 38219

You can use the inspect module, like this:

import inspect
inspect.getfile(C.__class__)

Upvotes: 191

Soviut
Soviut

Reputation: 91714

This is the wrong approach for Django and really forcing things.

The typical Django app pattern is:

  • /project
    • /appname
      • models.py
      • views.py
      • /templates
        • index.html
        • etc.

Upvotes: 5

Jarret Hardie
Jarret Hardie

Reputation: 98072

try:

import sys, os
os.path.abspath(sys.modules[LocationArtifact.__module__].__file__)

Upvotes: 54

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