CODEWITHSUNDEEP
python
Pythorene
Pythorene

Reputation: 17

Printing index positions

I am given the following list

mylist=[25,42,58,31,20,11,42]

which I separated them into a new list

newlist=[[25,42,58,31],[20,11,42]]

Then I need to print it as follow. How do I code it in a way where all the index will be printed?

First sequence is : 0,1,2,3
Second sequence is : 4,5,6

Upvotes: 0

Views: 75

Answers (4)

j1-lee
j1-lee

Reputation: 13939

The following is one implementation using itertools.count:

import itertools

newlist=[[25,42,58,31],[20,11,42]]

cnt = itertools.count()
for i, sublst in enumerate(newlist):
    print(f"Sequence {i}:", [next(cnt) for _ in sublst])

# Sequence 0: [0, 1, 2, 3]
# Sequence 1: [4, 5, 6]

I personally find this method concise.

Upvotes: 4

justANewb stands with Ukraine
justANewb stands with Ukraine

Reputation: 4663

You can use the inflect package to convert 1, 2, 3 to 1st, 2nd, 3rd...

Quick prototype:

import inflect
p = inflect.engine()

for i in range(len(newlist)):
    print(f"{p.ordinal(i)} sequence is {','. join(map(str , seq))}}")

Upvotes: 0

mozway
mozway

Reputation: 260845

Assuming this only depends of newlist (i.e newlist is a valid split of mylist):

newlist=[[25,42,58,31],[20,11,42]]
start = 0
for i, l in enumerate(newlist):
    seq = range(start, start+len(l))
    start += len (l)
    print(f'sequence {i} is: {",".join(map(str,seq))}')

Output:

sequence 0 is: 0,1,2,3
sequence 1 is: 4,5,6

Upvotes: 1

PeptideWitch
PeptideWitch

Reputation: 2349

What you have here is a list of lists that you could interate through and count the results.

addition = 0
for idx, item in enumerate(newlist):
    if idx != 0:
       addition = len(newlist[idx-1])
    print(f"Sequence of item {idx+1}: {[i+addition for i in range(len(item))]}"

Upvotes: 0

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