CODEWITHSUNDEEP
groovyjenkins-groovy
user2995458
user2995458

Reputation: 61

In Groovy -How to iterate the version list at the exact index position and compare it in for loop?

I am trying to get the matched version of B='1.7' and start iteration and deploying the version till it match to version A='1.12' but it's not doing as expected.

​def C = ['1.0', '1.6', '1.7', '1.7.1', '1.10.0', '1.11.0', '1.12']
A='1.12'
B='1.7'

     for(item in C){
       //println item
       if (B >= item && A <= item) {         
          println "deploy the version ${item}"
       }
   } 
​

Output-

deploy the version 1.7
deploy the version 1.12

Expected output

deploy the version 1.7
deploy the version 1.7.1
deploy the version 1.10.0
deploy the version 1.11.0
deploy the version 1.12

Please help me what I am doing wrong and just want to know is this a correct way of version comparison?

Upvotes: 0

Views: 195

Answers (1)

Kaus2b
Kaus2b

Reputation: 845

I am assuming that your input list may not always be sorted. In that case:

def c = ['1.10.1', '1.0', '1.6', '1.7', '1.7.1', '1.10.0', '1.11.0', '1.12']
def high='1.12'
def low='1.7'

def compareVals = { leftVal, rightVal ->
    [leftVal, rightVal]*.tokenize('.')
        .with { a, b -> [a, b].transpose() 
        .findResult { x, y -> (x.toInteger() <=> y.toInteger()) ?: null}
         ?: a.size() <=> b.size()
    }
}

c.sort{s1, s2 -> compareVals(s1,s2)}
 .subList(c.indexOf(low), c.indexOf(high)+1)
 .each {println "Deploy Version ${it}"}

OUTPUT:

Deploy Version 1.7
Deploy Version 1.7.1
Deploy Version 1.10.0
Deploy Version 1.10.1
Deploy Version 1.11.0
Deploy Version 1.12

Upvotes: 1

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