CODEWITHSUNDEEP
pythonfabric
dustin999
dustin999

Reputation: 283

python fabric won't allow me to pipe output to less?

I'm setting up fabric for the first time, and having trouble piping the output from fabric to less. For example, if I run:

fabric deploy |less

(Where deploy is my deployment function)

I get the following error back from fabric:

IOError: [Errno 22] Invalid argument

This comes from a run() command on the remote host.

If I add pty=False to the run() arguments, it works. However, that means every run command, I need to add this argument. Not to mention, I believe it has implications with prompts and entering data (obviously for those cases I won't be piping to less).

How can I fix this? Should I just do tty=false for everything?

Upvotes: 1

Views: 1204

Answers (1)

dustin999
dustin999

Reputation: 283

Just for future reference, I resolved this by applying a patch to operations.py, as seen here:

http://code.fabfile.org/attachments/56/operations.patch

Otherwise, the code that would reproduce this problem is as follows:

from __future__ import with_statement
from fabric.api import *
from fabric.contrib.console import confirm
import re
import sys

def test():
    run('ls')

And the issue would come up if you did the following command:

fab -H myhost test |less

Hope this helps someone... I still don't understand why a bug this old still hasn't been patched in the latest release of fabric.

-Dustin

Upvotes: 2

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