Reputation: 137
I have more records of the same subject and predicate, but different object, like:
Alex hasFriend A
Alex hasFriend B
Alex hasFriend C
Alex hasFriend D
How could I query the data to get the result with comma separated values, like:
Alex hasFriend A, B, C, D
The SPARQL query is like this:
select distinct ?person ?friend where {
?person <http://www.example.com/hasFriend> ?friend.
}
Upvotes: 1
Views: 363
Reputation: 14391
Adding an answer to summarize the comment section above. The GROUP_CONCAT aggregate function can be used to achieve the results you are looking for. Note that the function allows you to specify the delimiter of your choice.
SELECT ?person (GROUP_CONCAT(?friend; separator=', ') AS ?friends)
WHERE
{
?person <http://www.example.com/hasFriend> ?friend
}
GROUP BY ?person
Upvotes: 3