CODEWITHSUNDEEP
javaandroidstringcompare
cj1098
cj1098

Reputation: 1600

String comparison issue

I'm trying to do something reallllly simple that apparently is extremely difficult in android. I just want to compare two strings to see if they are equal.

I have a temp variable with the value "Location" I have debugged this and it does indeed contain Location... So I tried this at first 

if(temp == "Location") { //do something }

But I already know that doesn't work. I then tried all the possible functions for a string such as:

.equals .contains .ignoreCaseEquals etc...

If anyone has any idea what to do please help. This is really getting annoying.

EDIT: Here is the function where I'm comparing the strings for those of you who want to see.

public String[] getData(){ 
    try {
        int tempGroupCount = 0;
        URL food_url = new URL (Constants.SERVER_DINING);
        BufferedReader my_buffer = new BufferedReader(new InputStreamReader(food_url.openStream()));
        temp = my_buffer.readLine();
        // prime read
        while (temp != null ){
            // check to see if readline equals Location
            Log.w("HERasdfsafdsafdsafE", temp);
            // start a new location
            if (temp.equals("Location")
            {
                groups[tempGroupCount] = temp;
                tempGroupCount++;
            }
                Log.w("HERasdfsafdsafdsafE", temp);
                //start for-loop to test to get child info
                //for(temp = my_buffer.readLine(); temp != "Location" && temp != null; groupCount++, childrenCount++){
                    //children[groupCount][childrenCount] = temp;
                //}

            temp = my_buffer.readLine();
        }
        my_buffer.close();
    } catch (MalformedURLException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        Log.e("IO EXCEPTION", "Exception occured in MyExpandableListAdapter:" + e.toString());
    }
    return groups;
    }

Upvotes: 0

Views: 324

Answers (8)

Just trying to help
Just trying to help

Reputation: 1

you may try the following to find out where your problem is.

final String LOCATION = "Location"; // just to make sure we use the very same character sequence

if (temp.equals(LOCATION)
{
    /* your code here */
}
else
{
    System.out.println("Location : " + Arrays.toString(LOCATION.getBytes(Charset.forName("UTF-8"))));
    System.out.println("temp     : " + Arrays.toString(temp.getBytes(Charset.forName("UTF-8"))));
}

This should print the byte representation of both Strings to standard out. If equals() returns false, the strings differ. Because of unprintable characters or similar looking characters it's sometimes difficult to find the difference. But the byte representation should show you.

(I'm not an android programmer, so I hope the functions exist on android JVM. And sorry for any typos and missing brackets - if any ;-)

Upvotes: 0

Mohammed Azharuddin Shaikh
Mohammed Azharuddin Shaikh

Reputation: 42016

public String[] getData(){ 
    try {
        int tempGroupCount = 0;
        URL food_url = new URL (Constants.SERVER_DINING);
        BufferedReader my_buffer = new BufferedReader(new InputStreamReader(food_url.openStream()));
        temp = my_buffer.readLine();
        // prime read
        while (temp != null ){
            // check to see if readline equals Location
            Log.w("HERasdfsafdsafdsafE", temp);
            // start a new location
            if (temp.toString().equalsIgnoreCase("Location")
            {
                groups[tempGroupCount] = temp;
                tempGroupCount++;
            }
                Log.w("HERasdfsafdsafdsafE", temp);
                //start for-loop to test to get child info
                //for(temp = my_buffer.readLine(); temp != "Location" && temp != null; groupCount++, childrenCount++){
                    //children[groupCount][childrenCount] = temp;
                //}

            temp = my_buffer.readLine();
        }
        my_buffer.close();
    } catch (MalformedURLException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        Log.e("IO EXCEPTION", "Exception occured in MyExpandableListAdapter:" + e.toString());
    }
    return groups;
    }

first try to convert "temp" into string then compare it, apply this may helps you

Upvotes: 0

Mohit Verma
Mohit Verma

Reputation: 3025

if(temp.equals("Location"))
{
         //your code here
}
does not work

try this
if(temp.contains("Location"))
{
         //your code here
}

Upvotes: 2

A. Abiri
A. Abiri

Reputation: 10810

Try doing this:

if (temp.toLowerCase().compareTo("location") == 0)

Upvotes: 0

Piraba
Piraba

Reputation: 7014

I am doing same scenario , its working fine.

    String result = responsePrimitiveData.toString();
if(!result.equals("0")){ 
     }

Upvotes: 0

Jon Skeet
Jon Skeet

Reputation: 1499830

equals does work. If temp.equals("Location") returns false, then your temp variable does not refer to a string with the value "Location".

There may be unprintable characters or other oddities about the string - I suggest you look at the length of the string to check. Alternatively, there can be other characters which look like the ASCII characters, but aren't. In the debugger, try examining the array and get at the underlying char array - check the Unicode value of each character.

Upvotes: 3

Cedekasme
Cedekasme

Reputation: 2037

if your variable temp is a String, you can also used the method compareTo(String).

if (temp.compareTo("Location") == 0) 
{ 
    //do something 
}

Upvotes: 0

Rasel
Rasel

Reputation: 15477

try like

if(temp.equals("Location")) { //do something }

and 

while (!temp.equals("")){

Upvotes: 0

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