CODEWITHSUNDEEP
pythonsympysimplify
Shoaib Mirzaei
Shoaib Mirzaei

Reputation: 522

sympy not ignoring unimportant decimals in exponential expression

I have a code that calculate some mathematical equations and when I want to see the simplified results, it can not equate 2.0 with 2 inside power, which is logical since one is float and the other is integer. But decision was sympys where to put these two values, not mine.

Here is the expression in my results that sympy is not simplifying

from sympy import *

x = symbols('x')

y = -exp(2.0*x) + exp(2*x)
print(simplify(y)) # output is -exp(2.0*x) + exp(2*x)

y = -exp(2*x) + exp(2*x)
print(simplify(y)) # output is 0

y = -2.0*x + 2*x
print(simplify(y)) # output is 0

y = -x**2.0 + x**2
print(simplify(y)) # output is -x**2.0 + x**2

is there any way working around this problem? I am looking for a way to make sympy assume that everything other than symbols are floats, and preventing it to decide which one is float or integer.

this problem has been asked before by Gerardo Suarez but not with a satisfactory answer.

Upvotes: 1

Views: 214

Answers (1)

KZiovas
KZiovas

Reputation: 4719

There is another sympy function you can use called nsimplify. When I run your examples they all return zero:

from sympy import *

x = symbols("x")

y = -exp(2.0 * x) + exp(2 * x)
print(nsimplify(y))  # output is 0

y = -exp(2 * x) + exp(2 * x)
print(nsimplify(y))  # output is 0

y = -2.0 * x + 2 * x
print(nsimplify(y))  # output is 0

y = -(x ** 2.0) + x ** 2
print(nsimplify(y))  # output is 0

Update As @Shoaib Mirzaei mentioned you can also use the rational argument in the simplify() function like this:

simplify(y,rational=True)

Upvotes: 2

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