CODEWITHSUNDEEP
pythonpython-typing
Emilia Delizia
Emilia Delizia

Reputation: 353

Type hints in python puzzled by from typing import Any

I have the following exercise:

Annotate with correct types the parameters and the return values of the functions, as well as of the variables, in the program in the other panel. For that, you only need to replace every occurrence of Any, except for the very first line, by an appropriate type.

Example: The first Any in line 3, i.e., n: Any, must be replaced by int. You can see that from the line 9.

While I understand the theory of type hints I don't get the exercise, most probably because I do not get at this point the use of Any. Furthermore the exercise is ambiguous, it says to replace every occurrence of Any.

If this is the case would the first line be:

def get_half(n : int) -> int:
  return n/2

If so it does not work.

from typing import Any #do not edit this line

def get_half(n : Any) -> Any:
  return n/2

def print_half(n : Any) -> Any:
  print(n/2)
  
y = get_half(10)
print_half(20)

def is_present(s : Any, char : Any) -> Any:
  found : Any = False
  l : Any = len(s)
  for i in range(0, l):
    if s[i] == char:
      found = True
  return found

print(is_present("john", "h"))

Upvotes: 0

Views: 315

Answers (2)

Emilia Delizia
Emilia Delizia

Reputation: 353

This is the correct solution thanks to your answers

This link was very useful

https://mypy-play.net/?mypy=latest&python=3.10

from typing import Any #do not edit this line

def get_half(n : int) -> float:
  return n/2

def print_half(n : int) -> None:
  print(n/2)
  
y = get_half(10)
print_half(20)

def is_present(s : str, char : str) -> bool:
  found : bool = False
  l : int = len(s)
  for i in range(0, l):
    if s[i] == char:
      found = True
  return found

print(is_present("john", "h"))

Upvotes: 1

Sefan
Sefan

Reputation: 709

The first any is an int like the example said def get_half(n : int) -> Any: and the return value will differ depending if your exercise is for python 2 or 3.

Python2: def get_half(n : int) -> int:

Python3: def get_half(n : int) -> float:

The reason for this is that Python 2 always returns an int if you divide and int with an int. int/int=int And Python 3 uses "true division" and therefor returns an float. int/int=float

For more info see: https://en.wikibooks.org/wiki/Python_Programming/Operators

Upvotes: 0

Related Questions