Reputation: 981
I have the following dataframe:
df = pd.DataFrame({'timestamp' : [10,10,10,20,20,20], 'idx': [1,2,3,1,2,3], 'v1' : [1,2,4,5,1,9], 'v2' : [1,2,8,5,1,2]})
timestamp idx v1 v2
0 10 1 1 1
1 10 2 2 2
2 10 3 4 8
3 20 1 5 5
4 20 2 1 1
5 20 3 9 2
I'd like to group data by timestamp and calculate the following cumulative statistic: np.sum(v1*v2) for every timestamp. I'd like to see the following result:
timestamp idx v1 v2 stat
0 10 1 1 1 37
1 10 2 2 2 37
2 10 3 4 8 37
3 20 1 5 5 44
4 20 2 1 1 44
5 20 3 9 2 44
I'm trying to do the following:
def calc_some_stat(d):
return np.sum(d.v1 * d.v2)
df.loc[:, 'stat'] = df.groupby('timestamp').apply(calc_some_stat)
But for stat columns I receive all NaN values - what is wrong in my code?
Upvotes: 2
Views: 43
Reputation: 35686
We want groupby transform
here not groupby apply
:
df['stat'] = (df['v1'] * df['v2']).groupby(df['timestamp']).transform('sum')
If we really want to use the function we need to join
back to scale up the aggregated DataFrame:
def calc_some_stat(d):
return np.sum(d.v1 * d.v2)
df = df.join(
df.groupby('timestamp').apply(calc_some_stat)
.rename('stat'), # Needed to use join but also sets the col name
on='timestamp'
)
df
:
timestamp idx v1 v2 stat
0 10 1 1 1 37
1 10 2 2 2 37
2 10 3 4 8 37
3 20 1 5 5 44
4 20 2 1 1 44
5 20 3 9 2 44
The issue is that groupby apply
is producing summary information:
timestamp
10 37
20 44
dtype: int64
This does not assign back to the DataFrame naturally as there are only 2 rows when the initial DataFrame has 6. We either need to use join
to scale these 2 rows up to align with the original DataFrame, or we can avoid all of this using groupby transform
which is designed to produce a:
like-indexed DataFrame on each group and return a DataFrame having the same indexes as the original object filled with the transformed values
Upvotes: 3