CODEWITHSUNDEEP
pythondjango
Muhammet Aydoğan
Muhammet Aydoğan

Reputation: 321

How can I get date like(07.11.2021 ) from date name like (Monday,Tuesday...)

I' developing a django project and in my template user can select a day.As shown as bottom picture. enter image description here

And after day select post request is working.And in my views.py I can get the day name.Like(Monday,Tuesday,...). Using this knowledge, I want to get a date this week. For example, the coming value of request is Wednesday, and I want to get what date is Wednesday this week like (03.11.2021)

Upvotes: 0

Views: 236

Answers (2)

Thierno Amadou Sow
Thierno Amadou Sow

Reputation: 2573

create a file called utils.py and import it inside your views.py and your can pass it string like 'Sunday' it will give the correct date and make sure the first later is capitalyze. before passing to the function.This is just an idea you can make it better ).

from datetime import date,timedelta
import calendar
def find_day(week_day):
    my_date = date.today()
    a = calendar.day_name[my_date.weekday()]  
    weekdays = ['Sunday','Monday','Tuesday','Wednesday','Thursday','Friday','Saturday']
    now = weekdays.index(a)
    later = weekdays.index(week_day)
    date = my_date - timedelta(days= now - later)
    return date

Upvotes: 1

norok2
norok2

Reputation: 26886

I assume you have a certain data (e.g. today) and you want to know the date of another day of the week within the same week.

You could use datetime and time, to get the weekday as integer of today, compute the difference in days between the weekday you have and the one you target, and finally apply that difference to your original datetime.

The weekday is optionally converted to an integer using strptime() and trying all known weekday format strings. Do note that tm_wday as well as weekday() use the same convention for "Monday" -> 0 through "Sunday" -> 6, while %w and %u format codes use different conventions. It is crucial to compute the difference with integer weekdays obtained following the same convention. Hence, if weekday is given as an integer, the "Monday" -> 0 through "Sunday" -> 6 convention should be used.

import datetime
import time


def weekday_as_int(weekday):
    weekday = weekday.strip()
    result = None
    # %a -- Weekday as locale’s abbreviated name.
    # %A -- Weekday as locale’s full name.
    # %w -- Weekday as a decimal number, where 0 is Sunday and 6 is Saturday.
    # %u -- ISO 8601 weekday as a decimal number where 1 is Monday and 7 is Sunday
    for fmt in ("%a", "%A", "%w", "%u"):
        try:
            result = time.strptime(weekday, fmt).tm_wday
        except ValueError:
            pass
        if result is not None:
            return result
    if not result:
        raise ValueError(f'Could not parse `{weekday}` as week day')


def get_date_for_weekday(curr_date, weekday):
    if not isinstance(weekday, int):
        weekday = weekday_as_int(weekday)
    curr_weekday = curr_date.weekday()
    delta = weekday - curr_weekday
    return curr_date + datetime.timedelta(days=delta)


# datetime.date(2021, 11, 5) is a Friday
get_date_for_weekday(datetime.date(2021, 11, 5), "Monday")
# datetime.date(2021, 11, 1)

get_date_for_weekday(datetime.date(2021, 11, 5), "Friday")
# datetime.date(2021, 11, 5)

get_date_for_weekday(datetime.date(2021, 11, 2), "wed")                                                                         
# datetime.date(2021, 11, 3)

get_date_for_weekday(datetime.date.today(), "mon")
# datetime.date(2021, 11, 1)  # <-- this output only this week

Upvotes: 0

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