CODEWITHSUNDEEP
jenkinsgroovyjenkins-plugins
arielma
arielma

Reputation: 1398

How to bring list of jenkins nodes to Active choice parameter and present only those for the current logged in user

I have Jenkins job with active choice parameter with the name Computer. Which groovy script I should write to bring me all the Nodes names, and present only the one for the current logged in user? All nodes are with the label Desktop. I tried the below but it doesn't work:

import hudson.slaves.DumbSlave

def users = []
for (DumbSlave it : Hudson.instance.getSlaves()) {
  if(it.getLabelString().contains("Desktop")) {
    def currAgent = it?.computer?.name
    if(currAgent != null) {
      users.add(currAgent)
     }
  }
}

return users

Update (full answer with logged-on user, based on the below answer):

import jenkins.model.*
import hudson.model.User


def users = []
Jenkins.instance.nodes.each { node ->
  if(node.labelString.contains("Desktop")) {
    def currAgent = node?.computer
    def currAgentName = node?.computer?.name
    if(currAgentName != null) {
      def user = currAgent.systemProperties['user.name']?.toLowerCase()
      if (!users.contains(user) && user==User.current().toString()){
        users.add(currAgentName)
      }
    }
  }
}

return users

Upvotes: 3

Views: 1069

Answers (1)

Tidhar Klein Orbach
Tidhar Klein Orbach

Reputation: 2966

Try this:

import jenkins.model.*

def users = []
Jenkins.instance.nodes.each { node ->
    if(node.labelString.contains("Desktop")) {
        def currAgent = node?.computer?.name
        if(currAgent != null) {
            users.add(currAgent)
        }
    }
 }

 return users

Or make it Groovyer:

import jenkins.model.*

return Jenkins.instance.nodes.findAll { node ->
   node.labelString.contains("Desktop") &&
     node.computer.systemProperties["user.name"] == User.current().toString()
                                      }.collect { node ->
                                          node?.computer?.name }

Upvotes: 5

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