CODEWITHSUNDEEP
jqueryajax
Patrioticcow
Patrioticcow

Reputation: 27038

jquery, how to create a ajax request?

i have a function like this:

    $("#join").colorbox({
    onComplete:function(){
        // add code here
    },
    width:"530px", height:"500px", inline:true, href:"#add"
});

what i would like to do is onComplete:function() to create a ajax request to a xxx.php file.

i just want to make the request so that i can call a new url. i dont want to load anything from the new file and i dont want to redirect to that file, i just want to make a ajax call to it.

any ideas? thanks

Upvotes: 0

Views: 174

Answers (7)

Michael Sagalovich
Michael Sagalovich

Reputation: 2549

Using the $.ajax function. Like this:

$.ajax({
    url: 'myurl.php'
});

Won't this work?

Upvotes: 0

ShankarSangoli
ShankarSangoli

Reputation: 69905

Use $.get If you want to send anything to this page send in the second param

$.get("xxx.php", {});

Upvotes: 0

Tys
Tys

Reputation: 3610

If that is all you need, just do a $.get("xxx.php"); in you onComplete function.

Upvotes: 0

Matt
Matt

Reputation: 1265

$("#join").colorbox({
onComplete:function(){
    $.ajax({
       url: "xxx.php",
       type: "POST",
       data: "param1=value"
       success: function(){
          alert("success");
       }
    });
},
width:"530px", height:"500px", inline:true, href:"#add"

you can reference jquery's .ajax() method. http://api.jquery.com/jQuery.ajax/

Upvotes: 0

Paul
Paul

Reputation: 141839

You can use $.get() to send a GET request to your page. It will look like this:

$.get('xxx.php');

You can use the additional arguments to send data through GET, and to include a callback function if you want to do anything when the request finishes.

Upvotes: 0

David
David

Reputation: 218818

You would use the jQuery $.ajax function. Since you say you don't want to do anything with the response, you can just have an empty function for the success parameter of the .ajax() call. (Though I recommend against doing nothing with the response. You should at least check that it's good, even if you don't present anything to the user. Definitely don't ignore responses in the error parameter.)

Upvotes: 0

janhartmann
janhartmann

Reputation: 15003

Take a look at: http://api.jquery.com/jQuery.ajax/ 

$.ajax({
   type: "GET",
   url: "xxx.php",
   success: function(msg){
     alert("Success!");
   }
 });

Upvotes: 4

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