CODEWITHSUNDEEP
angulartypescript
Bary
Bary

Reputation: 53

Sort array of object by another array of object

I have two arrays of objects with the same length.

one= 
[
    { id: 3, name: 'a'}, 
    { id: 5, name: 'b'},
    { id: 4, name: 'c'}
];

two= 
[
    { id: 7, name: 'b'}, 
    { id: 6, name: 'c'},
    { id: 2, name: 'a'}
];

I want to sort array 'two' by name property that depends on array 'one'.

My solution is

const tempArray = [];
one.forEach((x) => {
   tempArray.push(two.find(item => item.name === x.name));

But is there a way to do this without creating tempArray?

I mean a one line solution?

Upvotes: 0

Views: 618

Answers (1)

Lesiak
Lesiak

Reputation: 25966

You could use map function:

const tempArray = one.map(x => two.find(item => item.name === x.name));

Alternatively, if you are not striving for brevity:

const nameToPosMap = Object.fromEntries(one.map((x, idx) => [x.name, idx]));
two.sort((i1, i2) => nameToPosMap[i1.name] - nameToPosMap[i2.name])

This may be faster as it avoids repeated find calls.

Upvotes: 2

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