Reputation: 85
I would like to know if there is a way to use setTimeout recursive implements with an arrow function, in order to use this
(refers to my class attribute for example) inside. Indeed, this = undefined
when i declare my setTimeout with a normal function
I got :
public currentIndex: number = 0;
setTimeout(function run(){
this.currentIndex++;
console.log(this.currentIndex); // returns undefined
setTimeout(run, 1000);
}, 1000)
Instead of :
setTimeout(() => {
this.currentIndex++;
console.log(this.currentIndex) // returns currentIndex value
setTimeout( ?? , 1000) // What should i put instead of '??' ?
}, 1000)
Upvotes: 3
Views: 1297
Reputation: 2155
This will create setTimeouts recursively
let currentIndex = 0;
const run = () => {
setTimeout(() => {
currentIndex++;
console.log(currentIndex);
run();
}, 1000);
}
run();
but better approach may be (I don't know your use case, so it is just maybe) to use setInterval()
let currentIndex = 0;
const interval = setInterval(() => {
currentIndex++;
console.log(currentIndex);
// stop interval
if (currentIndex >= 10) {
clearInterval(interval);
}
}, 1000);
Upvotes: 1
Reputation: 122
Its because arrow function does not create new context inside arrow function body but normal function does. So this in arrow function refers to parent scope context but this in normal function refers to its own context.
Upvotes: 1
Reputation: 386654
You could bind this
first and then use this function for all calls.
function run(reference) {
this.currentIndex++;
console.log(this.currentIndex); // returns undefined
setTimeout(reference, 1000, reference);
}
const runThis = run.bind(thisReference);
setTimeout(runThis, 1000, runThis);
Upvotes: 1
Reputation: 376
Probably the easiest way is to extract the arrow function into its own variable:
const run = () => {
this.currentIndex++;
console.log(this.currentIndex);
setTimeout(run, 1000);
};
setTimeout(run, 1000);
Though in this particular example you could simplify it even more using setInterval
instead of setTimeout
, avoiding the second setTimeout
call entirely.
Upvotes: 0