CODEWITHSUNDEEP
cscanfc-stringsfgetsstrlen
D. K.
D. K.

Reputation: 137

C program, strlen not counting whitespace?

i've written a simple program, where the program takes and imput and prints out the characters in sequence and counts them

char name[100];
int counter=0
printf("Enter name and surname:");
scanf("%s",&name);
    
for(int i=0; i<(strlen(name)); i++){
        printf("%c \n",name[i]);
        counter++;
printf("%d",counter)

for some reason , when i imput John Snow, it prints out only

J
o
h
n 
4

desired output

J
o
h
n

S
n
o
w
10

any help please? within reasonable skill level :D if posible no malloc() free() and memory things, its supposed to be quite easy :D

Upvotes: 0

Views: 767

Answers (1)

Vlad from Moscow
Vlad from Moscow

Reputation: 311088

For starters you have to write

scanf("%s",name);

instead of

scanf("%s",&name);

Secondly when the format string "%s" is used the function stops to enter characters as soon as a white space character is encountered.

You should write instead

scanf( " %99[^\n]", name );

Another approach is to use the function fgets

fgets( name, sizeof( name ), stdin );

The function can append the new line character '\n' to the entered string. To remove it you can write

name[ strcspn( name, "\n" ) ] = '\0';

Upvotes: 1

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