CODEWITHSUNDEEP
javareplaceapache-stringutils
HJW
HJW

Reputation: 23443

Apache StringUtils vs Java implementation of replace()

What would be the difference between Java 1.4.2's implementation of replace, and Apache 2.3's implementation? Is there a performance gain one over another?

Java 1.4.2 replace

Apache 2.3 replace

Upvotes: 10

Views: 29212

Answers (6)

Maitrik B Panchal
Maitrik B Panchal

Reputation: 7

To replace a string character with another string using StringUtil.Replace, I tried following and it's working fine for me to replace multiple string values from a single string.

String info = "[$FIRSTNAME$]_[$LASTNAME$]_[$EMAIL$]_[$ADDRESS$]";

String replacedString = StringUtil.replace(info, new String[] { "[$FIRSTNAME$]","[$LASTNAME$]","[$EMAIL$]","[$ADDRESS$]" }, new String[] { "XYZ", "ABC" ,"[email protected]" , "ABCD"});

This will replace the String value of info with newly provided value...

Upvotes: 0

sreenath V
sreenath V

Reputation: 131

public class Compare {

    public static void main(String[] args) {
        StringUtils.isAlphanumeric(""); // Overhead of static class initialization for StringUtils
        String key = "0 abcdefghijklmno" + Character.toString('\n') + Character.toString('\r');

        String key1 = replace1(key);
        String key2 = replace2(key);
    }


    private static String replace1(String key) {
        long start = System.nanoTime();
        key = StringUtils.replaceChars(key, ' ', '_');
        key = StringUtils.replaceChars(key, '\n', '_');
        key = StringUtils.replaceChars(key, '\r', '_');
        long end = System.nanoTime() - start;
        System.out.println("Time taken : " + end);
        return key;
    }

    public static String replace2(String word) {
        long start = System.nanoTime();
        char[] charArr = word.toCharArray();

        int length = charArr.length;
        for (int i = 0; i < length; i++) {
            if (charArr[i] == ' ' || charArr[i] == '\n' || charArr[i] == '\r') {
                charArr[i] = '_';
            }
        }

        String temp = new String(charArr);
        long end = System.nanoTime() - start;
        System.out.println("Time taken : " + end);
        return temp;
    }
}

Time taken : 6400

Time taken : 5888

Times are almost the same!

I've edited the code to drop out overheads of replace2 which were not because of JDK implementation.

Upvotes: 3

Bozho
Bozho

Reputation: 597056

  • String.replace(char, char) can't replace whole strings
  • you can have null values with StringUtils.replace(..).

String.replace(CharSequence s1, CharSequence s2) will do the same thing if the first string is not-null. Otherwise it will throw a NullPointerException

Upvotes: 1

Brian
Brian

Reputation: 6450

Apache's is quite a bit faster, if I recall correctly. Recommended.

Upvotes: 0

Joachim Sauer
Joachim Sauer

Reputation: 308021

The String.replace() method you linked to takes two char values, so it only ever replaces on character with another (possibly multiple times, 'though).

The StringUtils.replace() method on the other hand takes String values as the search string and replacement, so it can replace longer substrings.

The comparable method in Java would be replaceAll(). replaceAll() is likely to be slower than the StringUtils method, because it supports regular expressions and thus introduces the overhead of compiling the search string first and running a regex search.

Note that Java 5 introduced String.replace(CharSequence, CharSequence) which does the same thing as StringUtils.replace(String,String) (except that it throws a NullPointerException if any of its arguments are null). Note that CharSequence is an interface implemented by String, so you can use plain old String objects here.

Upvotes: 18

adarshr
adarshr

Reputation: 62583

1.4.2 replaces operates only with char arguments whereas the Apache 2.3 one takes in strings.

Upvotes: 2

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