DrEsperanto
DrEsperanto

Reputation: 45

Why is my code giving wrong output, translating inches into centimetres and vice versa

My code is giving incorrect output while everything seems to be alright.

The purpose of the code is to translate inches into centimetres and vice versa.

For example, with inpput cm then 6, the output is:

inch: 6, centimeter: 15.24

But it should be:

inch: 2.362, centimeter: 6


 
Code:
```py
def intocm():
    ms = input('What is it? (inch-in or centimeter-cm): ')
    am = int(input('How many of it: '))
    intocm = 2.54
    global inch
    global cm

    if ms == 'inch' or 'in':
        cm = am * intocm
        inch = am

    elif ms == 'centimeter' or ms == 'cm':
        cm = am
        inch = cm / intocm

    print(f'inch: {inch}, centimeter: {cm}')


intocm()

Upvotes: 0

Views: 78

Answers (4)

DrEsperanto
DrEsperanto

Reputation: 45

if ms=="inch" or "in" is wrong. It should be if ms=="inch" or ms=="in". Otherwise it'll be treated as if ((ms=="inch") or ("in"))

Upvotes: 0

Yunus Ot
Yunus Ot

Reputation: 1

The code is failing because of the first if condition. It should be similar to your elif condition.

In your code it is
if ms=="inch" or "in":

but it should be if ms=="inch" or ms=="in":

Upvotes: 0

eshirvana
eshirvana

Reputation: 24603

the issue is with logic in your if if ms=="inch" or "in":

you can write it better with in:

def intocm():
    ms=input("What is it? (inch-in or centimeter-cm): ")
    am=int(input("How many of it: "))
    intocm=2.54
    if ms in ["inch" , "in"]:
        cm=am*intocm
        inch=am
    elif ms in ["centimeter" , "cm"]:
        cm=am
        inch=cm/intocm
    print(f'inch: {inch}, centimeter: {cm}')
intocm()

Upvotes: 1

Elliott Frisch
Elliott Frisch

Reputation: 201507

You missed an equality test in your if statement, and you should be using float (not int). Like,

def intocm():
    ms=input("What is it? (inch-in or centimeter-cm): ")
    am=float(input("How many of it: "))
    intocm=2.54
    global inch
    global cm
    if ms=="inch" or ms=="in":
        cm=am*intocm
        inch=am
    elif ms=="centimeter" or ms=="cm":
        cm=am
        inch=cm/intocm
    print(f'inch: {inch}, centimeter: {cm}')

Which I ran

What is it? (inch-in or centimeter-cm): cm
How many of it: 2.54
inch: 1.0, centimeter: 2.54

(twice)

What is it? (inch-in or centimeter-cm): in
How many of it: 1
inch: 1.0, centimeter: 2.54

Which seems correct.

Upvotes: 1

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