CODEWITHSUNDEEP
javascriptregex
Syffys
Syffys

Reputation: 610

combine regex to match subgroups in different order

I have a string with may have one of the 2 below structure

(\w+){1}([!][a-zA-Z0-9>,]+)*([#]\d+)?

(\w+){1}([#]\d+)?([!][a-zA-Z0-9>,]+)*

some examples would be

"Abc1!deF2>Ghi3,4jlmNO!pQr5st#1400"
"Abc1#1400!deF2>Ghi3,4jlmNO!pQr5st"

The goal is to match as below

["Abc1", "!deF2>Ghi3,4jlmNO", "!pQr5st", "#1400"]
["Abc1", "#1400", "!deF2>Ghi3,4jlmNO", "!pQr5st"]

I can manage to get the result with 3 regex, but not with 1

const a = str.match(/\w+/)
const b = str.match(/([!][a-zA-Z0-9>,]+)/g)
const c = str.match(/[#]\d+/)

How can I get the expected result with a single regex ?

Upvotes: 1

Views: 39

Answers (1)

GOTO 0
GOTO 0

Reputation: 47672

Maybe use | to separate possible matches:

const regExp = /\w+|![a-zA-Z0-9>,]+|#\d+/g;

console.log("Abc1!deF2>Ghi3,4jlmNO!pQr5st#1400".match(regExp));
console.log("Abc1#1400!deF2>Ghi3,4jlmNO!pQr5st".match(regExp));

Also note that (\w+){1} is equivalent to \w+, and [!] and [#] are the same as ! and # respectively.

Upvotes: 1

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