CODEWITHSUNDEEP
juliahistogram
AfterFray
AfterFray

Reputation: 1851

UndefVarError: histogram not defined in Julia

I am trying to draw histogram as following :

using Plots; using PyPlot
pyplot() # Plots.PyPlotBackend()
x = 0:100;
result = rand(x,2000);
histogram(result)

However, it returns UndefVarError :

UndefVarError: histogram not defined

Stacktrace:
 [1] top-level scope
   @ In[156]:5
 [2] eval
   @ .\boot.jl:360 [inlined]
 [3] include_string(mapexpr::typeof(REPL.softscope), mod::Module, code::String, filename::String)
   @ Base .\loading.jl:1116

I followed Plotting a histogram in Julia but returns the error.

How can I resolve the error?

Upvotes: 2

Views: 661

Answers (1)

logankilpatrick
logankilpatrick

Reputation: 14551

I am unable to re-produce this error in Julia 1.6.3. When I run:

julia> using Plots; using PyPlot

julia> pyplot() # Plots.PyPlotBackend()
Plots.PyPlotBackend()

julia> x = 0:100;

julia> result = rand(x,2000);

julia> histogram(result)

I get:

Histogram image

Without any errors. This also works without running using PyPlot for me.

Upvotes: 2

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