CODEWITHSUNDEEP
regexpcre
Kid Diamond
Kid Diamond

Reputation: 2301

Match non-word characters until enclosing non-word characters if found

I want to match any non-word character from the beginning and end position of a string, but if it comes across a non-word character which encloses a string, I want it to stop matching right before it.

I created the following regex pattern:

^\W+(?!(\W+)((?!\1).)+\1)?

I expected it to match like is shown in the following image since it would match any non-word characters from the beginning of the string until it reached the enclosing quotes from the pattern in the negative lookahead:

!@#$%""<>test (string")-+/;,

But the result was this:

!@#$%""<>test (string")-+/;,

Regex101 Demo

What am I doing wrong?

Upvotes: 3

Views: 1384

Answers (1)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 627468

You need to use

^\W*?(\W)(?=.*?\b\1\W*$)

See the regex demo. Details:

  • ^ - start of string
  • \W*? - zero or more non-word chars, as few as possible
  • (\W) - a non-word char captured into Group 1
  • (?=.*?\b\1\W*$) - a positive lookahead that matches a location that is immediately followed with
    • .*? - any zero or more chars other than line break chars, as few as possible
    • \b - a word boundary
    • \1 - same value as in Group 1
    • \W* - zero or more non-word chars
    • $ - end of string.

Upvotes: 2

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