CODEWITHSUNDEEP
pythonlistfor-loop
unicorn
unicorn

Reputation: 3

Generating index for element in list of 10000 numbers

I have list of 10000 random numbers. I want the elements and their corresponding index for that element in the list between 5 and 500. I got to get the element by simple code

elements = [x for x in list_10000 if 5 <= x <= 500]

And for getting index I did

element_index = [list_10000.index(x) for x in list_10000 if 5 <= x <= 500]

The above index code took a lot of time but didn't execute. I have tried with arange and enumerate. But they gave different numbers of values than what I got with len(elements) How can I get index value ?? Any help would be great !! Thanking you in advance.

Upvotes: 0

Views: 409

Answers (2)

Timus
Timus

Reputation: 11351

You could use enumerate:

element_index = [i for i, x in enumerate(list_10000) if 5 <= x <= 500]

Upvotes: 2

Mahrkeenerh
Mahrkeenerh

Reputation: 1121

When you try to use index(1) two times, it will give you the same result both times, so having duplicate values will produce the same index.

You could instead use a dictionary, and immediately write both the value and it's index:

{i: list_10000[i] for i in range(len(list_10000)) if 5 <= list_10000[i] <= 500}

This will create a dictionary, where the index is the key, and the value is your number at the index.

Upvotes: 0

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