CODEWITHSUNDEEP
javaxpathgroovygpath
yegor256
yegor256

Reputation: 105143

How to find element by attribute value in GPath?

What is an alternative to this XPath //div[@id='foo'] in GPath? In general, where I can find this documentation?

Upvotes: 22

Views: 24170

Answers (4)

Nicolas Modrzyk
Nicolas Modrzyk

Reputation: 14197

Here is the corresponding snippet:

def node = new XmlSlurper().parseText(...)
def foo = node.depthFirst().findAll { it.name() == 'div' && it.@id == 'foo'}

A few other links you may want to read:

Upvotes: 31

user1708042
user1708042

Reputation: 1873

To mimic the expression //div[@id='foo'] the closest thing you can do with a GPath is:

def xml = new XmlParser().parseText(text)
xml.'**'.div.findAll { it.@id=="foo" }

the '**' is pretty much the same as '//' in your XPath. 

xml.'**'.div

will yield all the nodes of type div at any level.

Later filtering with findAll() with the given closure you get a list of nodes as you do in the XPath case

Upvotes: 3

Grant
Grant

Reputation: 11

what you need is this:

def root = new XmlSlurper().parseText(<locOfXmlFileYouAreParsing>.toURL().text)

def foundNode = root.'**'.find{ it.@id == "foo" }

its the double * that will let you find it without knowing the path. At least this is how I do it.

Upvotes: 1

winstaan74
winstaan74

Reputation: 1131

The previous poster gave you all that's required: Assuming your document has been slurped into xml, you want 

def foo = xml.path.to.div.find{it.@id == 'foo'}

to find a single result. Or findAll to find all results.

Upvotes: 9

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