Reputation: 985
I have added a list to the dataframe as shown below
new_df <- structure(list(ID = list(ID = "21", ID = "4"),
MET = structure(list(c("A", "B"), c("C", "D")), .Names = c("","")),
REGN = structure(list(c("ALL", "US"), "ALL"), .Names = c("", "")),
YEAR = list(YEAR = "2020", YEAR = "2020"),
WEEK = list(WEEK = c("12", "13", "14"), WEEK = "16"),
ANN = list(ANN = "Seller",ANN = "Rise")), row.names = 1:2, class = "data.frame")
new_df
ID MET REGN YEAR WEEK ANN
1 21 A, B ALL, US 2020 12, 13, 14 Seller
2 4 C, D ALL 2020 16 Rise
Suppose if i want to edit the rows here. For example, i need to edit 1 row and REGN column so
new_df[1,"REGN"] <- list(c(New "ALL", "New US"))
Warning message:
In `[<-.data.frame`(`*tmp*`, 1, "REGN", value = list(c("ALL", "USNew" :
replacement element 1 has 2 rows to replace 1 rows
Expected output
new_df
ID MET REGN YEAR WEEK ANN
1 21 A, B New ALL, New US 2020 12, 13, 14 Seller
2 4 C, D ALL 2020 16 Rise
Upvotes: 0
Views: 100
Reputation: 16836
You can use $
to access the column, then select the row with []
.
new_df$REGN[1] <- list(c("New ALL", "New US"))
Output
ID MET REGN YEAR WEEK ANN
1 21 A, B New ALL, New US 2020 12, 13, 14 Seller
2 4 C, D ALL 2020 16 Rise
Upvotes: 1