CODEWITHSUNDEEP
bash
BTR Naidu
BTR Naidu

Reputation: 1101

loop in bash does not perform integer comparison properly

I have below code

i=0
for s in / - \\ \| 
do 
  printf "\rWaiting for application start to finish $i $s"
  sleep 1
  ((i++))
  if [[ $i -gt 30 ]]
  then 
    break 
  fi
done

The loop always ends after 3 iterations. Any reason as why?

Upvotes: 0

Views: 39

Answers (2)

M. Nejat Aydin
M. Nejat Aydin

Reputation: 10123

This might be what you are looking for:

#!/bin/bash

a=('/' '-' '\' '|')
for ((i = 0; i < 30; ++i)); do
    printf '\rWaiting for application start to finish %d %s' \
            "$i" "${a[i%4]}"
    sleep 1
done
echo

Upvotes: 1

BTR Naidu
BTR Naidu

Reputation: 1101

My mistake. The for loop which has three arguments is exiting instead of the if condition failing.

Upvotes: 0

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