Reputation: 6826
How do I get Jackson to treat 'name' as if it had a @JsonProperty annotation?
public class SimpleClass {
private String name;
private String doNotSerialize;
public SimpleClass( @JsonProperty("name") String name ) {
this.name = name;
}
public String getName() {
return name;
}
public int getSum() {
return 1+1;
}
}
The way it is now, I get an error, Unrecognized field "sum", because it treats every getter as a serializable property.
If I add a class annotation:
@JsonAutoDetect( getterVisibility = JsonAutoDetect.Visibility.NONE )
I get an empty string when serializing. I was hoping that Jackson would see the @JsonProperty on the constructor parameter and figure it out.
If I change the class annotation to:
@JsonAutoDetect( getterVisibility = JsonAutoDetect.Visibility.NONE, fieldVisibility = JsonAutoDetect.Visibility.ANY )
Then I get the 'doNotSerialize' field included.
If I set a @JsonCreator on the constructor, and change my autodetect, I still get a blank string:
@JsonAutoDetect( getterVisibility = JsonAutoDetect.Visibility.NONE, fieldVisibility = JsonAutoDetect.Visibility.NONE, creatorVisibility = JsonAutoDetect.Visibility.ANY )
public class SimpleClass {
private String name;
private String doNotSerialize;
@JsonCreator
public SimpleClass( @JsonProperty("name") String name ) {
this.name = name;
}
public String getName() {
return name;
}
public int getSum() {
return 1+1;
}
}
What I'm hoping is that somehow I can tell Jackson to treat all the constructor parameters as serializable fields, and all other fields / setters as non-serializable.
Upvotes: 0
Views: 896
Reputation: 27994
If you want "sum" to be included in the serializad json but want to ignore it when deserializing you can do:
@JsonIgnoreProperties(ignoreUnknown=true)
public class SimpleClass {
// properties/getters
public int getSum() { return 1+1; }
}
If you want to remove "sum" entirely from the json you can do
@JsonIgnoreProperties({"sum"})
public class SimpleClass {
// properties/getters
public int getSum() { return 1+1; }
}
or
public class SimpleClass {
// properties/getters
@JsonIgnore
public int getSum() { return 1+1; }
}
Upvotes: 0
Reputation: 11431
You can use a filter to only serialise getters which have a matching field, e.g.
package org.example;
import com.fasterxml.jackson.annotation.JsonFilter;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.ser.BeanPropertyWriter;
import com.fasterxml.jackson.databind.ser.PropertyWriter;
import com.fasterxml.jackson.databind.ser.impl.SimpleBeanPropertyFilter;
import com.fasterxml.jackson.databind.ser.impl.SimpleFilterProvider;
import java.io.IOException;
import java.io.StringWriter;
public class App {
@JsonFilter("test")
public static class SimpleClass {
private String name;
private String doNotSerialize;
public SimpleClass(String name ) {
this.name = name;
}
public String getName() {
return name;
}
public int getSum() {
return 1+1;
}
}
public static void main( String[] args ) throws IOException {
SimpleFilterProvider filterProvider = new SimpleFilterProvider();
filterProvider.addFilter("test", new SimpleBeanPropertyFilter() {
@Override
protected boolean include(BeanPropertyWriter writer) {
return super.include(writer);
}
@Override
protected boolean include(PropertyWriter writer) {
String name = writer.getName();
Class clazz = writer.getMember().getDeclaringClass();
try {
clazz.getDeclaredField(name);
return super.include(writer);
} catch (NoSuchFieldException e) {
// ignore
return false;
}
}
});
ObjectMapper mapper = new ObjectMapper();
mapper.setFilterProvider(filterProvider);
StringWriter sw = new StringWriter();
mapper.createGenerator(sw).writeObject(new SimpleClass("foo"));
System.out.println(sw.toString());
}
}
I don't know your full requirements, but this should be a start.
I haven't tried to do what you actually, asked, that is, look at constructor parameters, but that should be possible too.
Upvotes: 1