CODEWITHSUNDEEP
java
hashprophet
hashprophet

Reputation: 11

Convert number to reversed array of digits (Scanner + Print-Method)

I want to get an Array with the reversed number when I invoke the method (Given a random non-negative number, you have to return the digits of this number within an array in reverse order.) I initalised a scanner, but whenever I execute, I only get the address in the heap I suppose (for example: [I@66a29884). I know this problem also occurs when we have String, which why we have the toString-Method. Is there a way I can print the array or the reversed numbers out in the console?

public class ConvertNumber {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        Long n = Long.parseLong(scanner.nextLine());
        digitize(n);
    }
    public static int[] digitize(long n) {
        int[] digitized =  new StringBuilder().append(n).reverse().chars().map(Character::getNumericValue).toArray() ;
        System.out.println(digitized);
        return  digitized;
}
}

Upvotes: 1

Views: 395

Answers (1)

Faheem azaz Bhanej
Faheem azaz Bhanej

Reputation: 2396

You have to change Long to String because [I@66a29884) is String. using java stream you can reverse string easily.

import java.util.stream.Stream;
import java.util.stream.Collectors;
import java.util.*;
public class Main
{
    public static String digitize(String n) {
        return Stream.of(n)
            .map(str->new StringBuilder(str).reverse())
            .collect(Collectors.joining(" "));
    }
    
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        String n = scanner.next();
        System.out.print(digitize(n));
    }
}

Upvotes: 3

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