Reputation: 61
I'm trying to use "markers" for the line function with plotly 5.4.0
import plotly.express as px
df_temp = df_temp[df_temp.date_str.isin(selected_dates)]
fig = px.line(df_temp, x='trialID', y='reaction_time', color='date_str', markers=True,
title=f'Graph2. Intervention status: {status}')
i get the error:
TypeError: line() got an unexpected keyword argument 'markers'
i read that it's about an update but i don't think it's that. does anyone know what it could be?
Upvotes: 6
Views: 10124
Reputation: 466
Plotly's documentation marks this as a valid parameter:
markers (boolean (default False)) – If True, markers are shown on lines.
taken from plotly.express.line documentation
For me upgrading the plotly version fixed it. You can check the plotly version with import plotly
and then plotly.__version__
. (You can do that for any library actually). I can't seem to find history on the API spec as to when they introduced, but from the answers above it works in 5.4, and for me it didn't work in 5.1.
Upvotes: 0
Reputation: 31226
df_temp, selected_dates, status
import plotly.express as px
import pandas as pd
import numpy as np
df_temp = pd.DataFrame(
{
"date_str": np.repeat(pd.date_range("1-jan-2021", periods=10), 10).astype(str),
"trialID": np.tile(np.arange(10), 10),
"reaction_time": np.random.uniform(0, 2, 100),
}
)
selected_dates = pd.Series(df_temp["date_str"].unique()).sample(5).values
status = "my favorite status"
df_temp = df_temp[df_temp.date_str.isin(selected_dates)]
fig = px.line(
df_temp,
x="trialID",
y="reaction_time",
color="date_str",
markers=True,
title=f"Graph2. Intervention status: {status}",
)
fig
Upvotes: 0