Reputation: 451
I have to run a group of functions every so often, during the day I have to run them every 2 minutes, in the evening they need to run every 3 minutes and at night they need to run every 5 minutes. Right now I'm running them like this, with every function running every 2 minutes at all times of the day.
const function1 = () => DO_SOMETHING
const function2 = () => DO_SOMETHING_ELSE
const function3 = () => DO_SOMETHING_ANTOTHER_THING
setInterval(() => {
function1()
}, 1000 * 60 * 2)
setInterval(() => {
function2()
}, 1000 * 60 * 2)
setInterval(() => {
function3()
}, 1000 * 60 * 2)
Does anyone know how I can set this up so that the time variable changes depening on what time of day it is?
Upvotes: 0
Views: 749
Reputation: 9984
This can be done by using a setTimeout
that triggers itself, instead of a setInterval
.
Overview:
Date().getHours()
to find the time.Example:
(You can change the definition of "evening" and "night" using the two if statements)
// This is required if you ever want to use clearTimeout()
let timeoutRefernce = null
// Run the desired code after X amount of time
const result = () => {
// Start a new iteration of the timer
newTimeout()
// Run your resulting code
// e.g. Call function1, function2 and function3
console.log('Result')
}
const newTimeout = () => {
const time = new Date().getHours()
let minutes = 2
// Is it evening? (Between 5pm and 10pm)
if (time > 17 && time < 22) {
minutes = 3
}
// Is it night? (Between 10pm and 6am)
if (time > 22 || time < 6) {
minutes = 5
}
// Create a new timeout with the relevant duration
timeoutRefernce = setTimeout(result, 1000 * 60 * minutes)
console.log(`Hour: ${time}, New timeout created with duration ${minutes} minutes`)
}
// Run the first timeout on load
newTimeout()
Upvotes: 3