CODEWITHSUNDEEP
matrixjulia
Shixiang Wang
Shixiang Wang

Reputation: 2381

julia how to quickly generate matrix by row from range

How can I quickly generate matrix by row from range?

For example, given

my_example_matrix = [[1 2 3]
                     [4 5 6]
                     [7 8 9]]

How can I generate the matrix fastly by using range 1:9?

Best.

Upvotes: 2

Views: 176

Answers (1)

BatWannaBe
BatWannaBe

Reputation: 4510

This is quick in a way because no part of it allocates memory, so the length of the range won't matter.

julia> transpose(reshape(1:9, (3, 3)))
3×3 LinearAlgebra.Transpose{Int64,Base.ReshapedArray{Int64,2,UnitRange{Int64},Tuple{}}}:
 1  2  3
 4  5  6
 7  8  9

Upvotes: 2

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