CODEWITHSUNDEEP
pythonpython-3.xsystem
God-status
God-status

Reputation: 311

Is there a way to detect if a computer is brought out of sleep mode?

Problem

I want to write a program in Python, where a script executes when it detects that it has been brought out of sleep mode. E.g I am using a laptop. When I open the laptop, the script should run. Is there a way to detect this and then run a script? Is there a module for listening for such events?

Goal

The ultimate goal is a sort of security system, where an alert is sent to a users phone, if their computer is used. I have an idea for the alert sending part, I just can't figure out how to trigger the program in the first place.

The basic format should look something like this:
if computer_active == True:
    alert.send("Computer accessed")

Obviously it would look more complicated than that, but that's the general idea.

I'm running Python3.10.0 on MacOSX v10.15.7

Any help is greatly appreciated!

Upvotes: 2

Views: 2103

Answers (3)

mo FEAR
mo FEAR

Reputation: 693

systemd has an option to execute a (python) script once after every wake-up. So you can create a script that knows a wake up has happened each time it runs, and you can take it from there. If you need to inform a script that must be always running, use interprocess communication, specifically events. See multiprocessing, specifically SyncManager (although I find BaseManager & passing a standalone Event object easier).

Upvotes: 0

TheConfax
TheConfax

Reputation: 184

Question is old, but since I was looking for the same thing and I did not find anything on the web...

import win32com.client

colMonitoredEvents = win32com.client.Dispatch("WbemScripting.SWbemLocator").ConnectServer(".", "root\cimv2").ExecNotificationQuery("Select * from Win32_PowerManagementEvent")

while True:
    objLatestEvent = colMonitoredEvents.NextEvent()
    if objLatestEvent.EventType == 7:
        pass #do your stuff here

Event based, run it indefinitely with low CPU usage and do stuff when the event ID is 7; event 4 should be catched instead when entering sleep. Note that with event 4 the action should be very quick or likely it will not complete before the PC goes to sleep.

Upvotes: 0

Andreas Florath
Andreas Florath

Reputation: 4612

A maybe-better-than-nothing-solution. It's hacky, it needs to run always, it's not event driven; but: it's short, it's configurable and it's portable :-)

'''
Idea: write every some seconds to a file and check regularly.
It is assumed that if the time delta is too big,
the computer just woke from sleep.
'''

import time

TSFILE="/tmp/lastts"
CHECK_INTERVAL=15
CHECK_DELTA = 7

def wake_up_from_sleep():
    print("Do something")

def main():
    while True:
        curtime = time.time()
        with open(TSFILE, "w") as fd:
            fd.write("%d" % curtime)
        time.sleep(CHECK_INTERVAL)
        with open(TSFILE, "r") as fd:
            old_ts = float(fd.read())
        curtime = time.time()
        if old_ts + CHECK_DELTA < curtime:
            wake_up_from_sleep()

if __name__ == '__main__':
    main()

Upvotes: 1

Related Questions