CODEWITHSUNDEEP
c++
SPB
SPB

Reputation: 4218

how to convert string in integer numbers

I am receiving string such as "2011-08-12,02:06:30" from the server which specifies data and time.

But how to convert it into int and store like

int year = 2011, month =08, day = 14, h = 02, min = 06, sec=30.

Upvotes: 1

Views: 233

Answers (4)

Eric Z
Eric Z

Reputation: 14535

You can use stringstream class in C++.

#include <iostream>
// for use of class stringstream
#include <sstream>

using namespace std;

int main()
{
   string str = "2011-08-12,02:06:30";
   stringstream ss(str);
   int year, month, day, h, min, sec;

   ss >> year;
   ss.ignore(str.length(), '-');
   ss >> month;
   ss.ignore(str.length(), '-');
   ss >> day;
   ss.ignore(str.length(), ',');
   ss >> h;
   ss.ignore(str.length(), ':');
   ss >> min;
   ss.ignore(str.length(), ':');
   ss >> sec;

   // prints 2011 8 12 2 6 30
   cout << year << " " << month << " " << day << " " << h << " " << min << " " << sec << " ";
}

Upvotes: 4

Jason
Jason

Reputation: 32538

You can also use the strptime() function on any POSIX-compliant platform, and save the data into a struct tm structure. Once in the format of a struct tm, you will also have some additional liberties to take advantage of other POSIX functions the time format as defined by struct tm.

For instance, in order to parse the string being sent back from your server, you could do the following:

char* buffer = "2011-08-12,02:06:30";
struct tm time_format;
strptime(buffer, "%Y-%d-%m,%H:%M:%S", &time_format);

Upvotes: 1

MarkD
MarkD

Reputation: 4954

You could either write your own string parser to parse the string into the necessary components (something like a Finite State Machine design would be good here), or...

Don't re-invent the wheel, and use something like the Boost Date & Time library.

Upvotes: 3

Perception
Perception

Reputation: 80633

The sscanf function will help you out much here.

int year, month, day, h, min, sec;
char * data = "2011-08-12,02:06:30";
sscanf(data, "%d-%d-%d,%d:%d:%d", &year, &month, &day, &h, &min, &sec);

Upvotes: 4

Related Questions