Reputation: 1369
I'm trying to implement a const_iterator for my binary tree but when I try to compile this main:
#include "rbtree.hpp"
#include <iostream>
int main(void) {
rbtree< int > t;
t.insert(9);
t.insert(8);
t.insert(7);
t.insert(6);
t.insert(5);
t.insert(1);
t.insert(2);
t.insert(3);
t.insert(4);
for (rbtree< int >::const_iterator it = t.begin(); it != t.end())
std::cout << *it << std::endl;
return 0;
}
the compiler (clang++) outputs:
test.cpp:27:37: error: no viable conversion from 'base_iterator<rbtree<int, std::allocator<int>, unsigned long, long>::rbnode>' to 'base_iterator<const rbtree<int, std::allocator<int>, unsigned long, long>::rbnode>'
for (rbtree< int >::const_iterator it = t.begin(); it != t.end())
^ ~~~~~~~~~
./rbtree.hpp:172:5: note: candidate constructor not viable: no known conversion from 'rbtree<int, std::allocator<int>, unsigned long, long>::iterator' (aka 'base_iterator<rbtree<int, std::allocator<int>, unsigned long, long>::rbnode>') to 'const rbtree<int, std::allocator<int>, unsigned long, long>::rbnode *' for 1st argument
base_iterator(node_type *from) : _ptr(from) { }
^
./rbtree.hpp:173:5: note: candidate constructor not viable: no known conversion from 'rbtree<int, std::allocator<int>, unsigned long, long>::iterator' (aka 'base_iterator<rbtree<int, std::allocator<int>, unsigned long, long>::rbnode>') to 'const rbtree<int, std::allocator<int>, unsigned long, long>::base_iterator<const rbtree<int, std::allocator<int>, unsigned long, long>::rbnode> &' for 1st argument
base_iterator(const base_iterator &other) : _ptr(other._ptr) { }
^
1 error generated.
the base_iterator< node_type > class is a public type of the rbtree
class (rbnode
is also a public type of rbtree
)
Here's the code of my base_iterator
class:
template <
typename node_type
> class base_iterator : public std::iterator<
std::bidirectional_iterator_tag,
T, // fix, was node_type
difference_type
> {
public:
base_iterator() : _ptr(NULL) { }
base_iterator(node_type *from) : _ptr(from) { }
base_iterator(const base_iterator &other) : _ptr(other._ptr) { }
~base_iterator() { }
base_iterator &operator =(const base_iterator &other) {
_ptr = other._ptr;
}
T &operator *(void) { return *_ptr->_data; }
T *operator ->(void) { return _ptr->_data; }
base_iterator &operator ++(void) {
if (_ptr) {
if (_ptr->_right) {
_ptr = _ptr->_right;
while (_ptr->_left) _ptr = _ptr->_left;
} else {
while (
_ptr->_parent
&& _ptr->_parent->_right == _ptr
) _ptr = _ptr->_parent;
if (!_ptr->_parent) return base_iterator();
}
}
return _ptr;
}
base_iterator operator ++(int) {
base_iterator backup(_ptr);
++this;
return backup;
}
base_iterator &operator --(void) {
if (_ptr) {
if (_ptr->_left) {
_ptr = _ptr->_left;
while (_ptr->_right) _ptr = _ptr->_right;
} else {
while (
_ptr->_parent
&& _ptr->_parent->_left == _ptr
) _ptr = _ptr->_parent;
if (!_ptr->_parent) return base_iterator();
}
}
return _ptr;
}
base_iterator operator --(int) {
base_iterator backup(_ptr);
--this;
return backup;
}
private:
node_type *_ptr;
};
and the typedefs for iterator
and const iterator
, and iterator functions in my rbtree
class
typedef base_iterator< rbnode > iterator;
typedef base_iterator< const rbnode > const_iterator;
typedef ft::reverse_iterator< iterator > reverse_iterator;
typedef ft::reverse_iterator< const_iterator > const_reverse_iterator;
iterator begin(void) { return iterator(_begin); } // fix, was return _begin;
const_iterator begin(void) const {
return const_iterator(_begin);
}
iterator end(void) { return iterator(); }
const_iterator end(void) const { return const_iterator(); }
reverse_iterator rbegin(void) { return iterator(_rbegin); }
const_reverse_iterator rbegin(void) const {
return const_iterator(_rbegin);
}
reverse_iterator rend(void) { return iterator(); }
const_reverse_iterator rend(void) const { return const_iterator(); }
I also edited private variables of rbtree
class:
size_type _size;
rbnode *_root;
rbnode *_begin; // was iterator
rbnode *_rbegin; // was iterator
So technically this should work, so why doesn't it ? it seems that the wrong function is called (iterator
one instead of const_iterator
one).
I saw from your answers that a const iterator must be convertible to an iterator ? so does that mean that I have to use the same type for both ?
Upvotes: 0
Views: 374
Reputation: 264401
You have to remember that templated types are completely independant.
base_iterator<X>
base_iteraotr<const X>
Are completely different types.
Your compiler is complaining that there is no constructor (or conversion operator) in base_iteraotr<const X>
that accepts base_iteraotr<X>
(a completely different type).
Upvotes: 1