CODEWITHSUNDEEP
pythoncharacterseparator
Laurent Salé
Laurent Salé

Reputation: 29

split-string-every-nth-character with nth+1 separator '0'

I have a serie of digits that are string, for example : IN : '01110100001101001001110100'

I want to split as follow: OUT: ['01110100', '0', '01101001', '0','01110100]

We can notice that ninth '0' is a separator of list of digits that are binary.

Said otherwise : first eighth, sperator'0',next height, separator '0', next height, separator '0', etc

I know how to split using nth element (Split string every nth character?), but the issue here is a bit more complicated:there is a separator '0'

Thanks a lot for your help.

Kindest regards

Upvotes: 1

Views: 146

Answers (2)

Barmar
Barmar

Reputation: 781503

You can use a regular expression with capture groups.

import re

instr = '01110100001101001001110100'
outlist = list(sum(re.findall(r'(\d{8})(\d)', instr), ()))

print(outlist)

re.findall() returns a list of tuples, list(sum(..., ()) flattens it into a single list.

Upvotes: 1

Paul M.
Paul M.

Reputation: 10809

You just want to alternate between grabbing a slice of length 8, and then a slice of length 1, right?

def get_slices(string):
    from itertools import islice, cycle

    string_iter = iter(string)
    slice_lens = cycle([8, 1])

    while slc := "".join(islice(string_iter, next(slice_lens))):
        yield slc

print(list(get_slices("abcdefghijklmnopqr")))

Output:

['abcdefgh', 'i', 'jklmnopq', 'r']

Upvotes: 1

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