Reputation:
I have a txt file and each line has a set of random strings, I need to select only the lines that contains only the characters: 1234567890qwertyuiopasdfghjklzxcvbnm-._~
I'm reading line by line and verifying char by char, I don't think it's the best way to do that, and I think a RegEx would be perfect.
So can anybody help with with a pattern for this?
thanks!
Upvotes: 2
Views: 210
Reputation: 23289
If I understand you well, you could go with this:
/^([-0-9a-zA-Z._~]\n)+$/
It is case-insensitive, check for end of line and doesn't match an empty line.
Upvotes: 2
Reputation: 89043
/^[-0-9a-z._~]*$/
^ :: matches the start of a string/start of a line
[ :: start of a character class, means match any one of the contained characters
- :: dash has a special meaning in character classes, so to avoid having it interpreted for its special meaning, list it first
0-9 :: shorthand for 0123456789 in a character class
a-z :: shorthand for abcdefghijklmnopqrstuvwxyz in a character class
._~ :: means exactly these characters in a character class
] :: end of the character class
* :: match zero or more of the previous atom (in this case, the character class)
$ :: matches the end of a string/end of a line
Upvotes: 9
Reputation: 95516
It doesn't take much to realize that the regular expression should be equivalent to ^[1234567890qwertyuiopasdfghjklzxcvbnm\-._~]*$
. From there you can narrow it down trivially, replacing with 0-9
, a-z
, etc. . You should learn the basics of regular expressions before using answers you get from others.
Upvotes: 0