CODEWITHSUNDEEP
pythonlistmatrixtype-conversion
Briana
Briana

Reputation: 19

Converting chars in 2D list to int values python

I'm trying to convert this maze:

[['#', '#', '#', '#', '#', '#'],
 ['#', 'o', '#', ' ', '#', '#'],
 ['#', ' ', '#', ' ', '#', '#'],
 ['#', ' ', ' ', 'x', '#', '#'],
 ['#', '#', '#', '#', '#', '#']]

to this:

[[0, 0, 0, 0, 0, 0],
 [0, 1, 0, 1, 0, 0],
 [0, 1, 0, 1, 0, 0],
 [0, 1, 1, 1, 0, 0],
 [0, 0, 0, 0, 0, 0]]

Is there a quick way to do convert the char values to ints? I don't know exactly what I need to be searching for. Also, what is the best way to traverse this?

Upvotes: 0

Views: 52

Answers (3)

Shadowcoder
Shadowcoder

Reputation: 972

A simple one liner:

x = [[int(i != '#') for i in row] for row in Matrix]

i != '#' checks if i is # or not and returns True or False. Then True and False are converted to 1 and 0 respectively.

Upvotes: 0

Wolfgang
Wolfgang

Reputation: 1398

t = [['#', '#', '#', '#', '#', '#'],
 ['#', 'o', '#', ' ', '#', '#'],
 ['#', ' ', '#', ' ', '#', '#'],
 ['#', ' ', ' ', 'x', '#', '#'],
 ['#', '#', '#', '#', '#', '#']]

In 1 line

x = [[1 if a != "#" else 0 for a in p] for p in t]

Result

print(DataFrame(x))
   0  1  2  3  4  5
0  0  0  0  0  0  0
1  0  1  0  1  0  0
2  0  1  0  1  0  0
3  0  1  1  1  0  0
4  0  0  0  0  0  0

Upvotes: 0

Ratery
Ratery

Reputation: 2917

matrix = [['#', '#', '#', '#', '#', '#'],
 ['#', 'o', '#', ' ', '#', '#'],
 ['#', ' ', '#', ' ', '#', '#'],
 ['#', ' ', ' ', 'x', '#', '#'],
 ['#', '#', '#', '#', '#', '#']]
for i in range(len(matrix)):
    matrix[i] = list(map(lambda x: int(x != '#'), matrix[i]))
print(matrix)

Upvotes: 2

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