CODEWITHSUNDEEP
rggplot2
seb
seb

Reputation: 2134

Pass by value in R

When trying to call grid.arrange to put multiple plots on a same ggplot2 graph, I first build a list of the plots I want. Then I build the corresponding argument list to call grid.arrange, as was explained in a previous question. This is my code (my dataframe is called manip):

args.list <- NULL;
plot.list <- NULL;
for (m in names(manip[2:10])) {
  plot.list <- c(plot.list, list(qplot(manip$side, y=manip[,m],ylab=m))
}
args.list <- c(plot.list, 1, 9)
names(args.list) <- c(names(manip)[2:10], list("nrow","ncol"))
do.call(grid.arrange, args.list)

This works, except that the 9 graphs are exactly the same! After checking, it turns out that the data is always the one corresponding to m=10. So my guess was that the value of m is not assigned in the loop, but evaluated later. However, the label ylab=m is assigned correctly and is different for all the graphs.

So I don't really get what the difference is and how the interpreter chooses when to evaluate m for the plots. Can someone explain?

Upvotes: 5

Views: 1190

Answers (3)

Andrie
Andrie

Reputation: 179398

I will first answer your question and then show an alternative using a facet plot.

Edited

The following, much simplified, code seems to work:

library(gridExtra)
manip <- mtcars
plot.list <- lapply(2:11, 
                    function(x)qplot(manip$mpg, y=manip[, x], 
                    ylab=names(manip)[x]))
do.call(grid.arrange, c(plot.list, nrow=10))

It produces this ugly plot: enter image description here

Without knowing your objectives, it is dangerous to try and give advice, I know. Nonetheless, have you considered using facets for your plot instead?

The following code is much simpler, executes quiker and produces a graph that is easier to interpret:

library(reshape2)
manip <- mtcars
mmanip <- melt(manip, id.vars="mpg")
str(mmanip)
ggplot(mmanip, aes(x=mpg, y=value)) + 
    geom_point(stat="identity") + 
    facet_grid(.~variable, scales="free")

enter image description here

Upvotes: 3

kohske
kohske

Reputation: 66842

The behavior is due to the lazy evaluation of R.

Here is a minimal(?) example:

d <- 1:3

args.list <- NULL;
plot.list <- NULL;
for (m in 1:3) {
 plot.list <- c(plot.list, list(qplot(d[m], d[m], ylab=letters[m])))
}

args.list <- c(plot.list, nrow=1, ncol=3)
do.call(grid.arrange, args.list)

in this case, d[m] is evaluated at the call of do.call. so m is 3 for all panel.

here is a workaround:

d <- 1:3

args.list <- NULL;
plot.list <- NULL;
for (m in 1:3) {
  plot.list <- c(plot.list,
    list(qplot(d, d, data=data.frame(d=d[m]), ylab=letters[m])))
}

args.list <- c(plot.list, nrow=1, ncol=3)
do.call(grid.arrange, args.list)

in this case, d[m] is evaluated at the call of qplot, and the d[m] is stored in the output object of qplot.

so, the simple solution is to pass data to qplot() or ggplot().

Upvotes: 4

Luciano Selzer
Luciano Selzer

Reputation: 10016

Perhaps it would be better to melt then data and use faceting?

library(ggplot2)
manip <- data.frame(car = row.names(mtcars), mtcars)
manip.m  <- melt(manip)
qplot(car, value, data = manip.m) + facet_wrap(~variable, scales = "free_y")

It need some polishing in the xlab

last_plot() + opts(axis.text.x = theme_text(angle = 90))

enter image description here

HTH

Upvotes: 2

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