CODEWITHSUNDEEP
unixebcdic
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Dodop

Reputation: 1

unix - how to remove a byte from a recursive position in a ebcdic file

I have an ebcdic file and need to remove a byte that recurs every n bytes:

For example: 00 00 00 25 00 0C 25 00 00 00 00 00 0C 25 00 78 25 69 67 4C 25 00 78 90 69 67 4C 25

I need to remove "25" from position 7, 14, 21, 28, the output would be:

00 00 00 25 00 0C 00 00 00 00 00 0C 00 78 25 69 67 4C 00 78 90 69 67 4C

I tried to use cut:

l=`stat -c%s myfile`

for (( i = 1 ; i <= $l ; i += 7 )) ; 
do

 m=`expr $i + 5`  
 cat myfile | cut -c$i-$m` >> fileout

done

But the output is not what I expect:

00 00 00 25 00 0C 0A 00 00 00 00 00 0C 0A 00 78 25 69 67 4C 0A 00 78 90 69 67 4C 0A

Can somebody help me?

Upvotes: 0

Views: 41

Answers (0)

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