CODEWITHSUNDEEP
linuxbash
Kiarash
Kiarash

Reputation: 8008

what's wrong with this simple bash command?

$i is not working... it's making me crazy!

for i in {1..200}; 
do echo "/scratch/inputTest/prob/timit.test.pg.list_10_$i_prob.bin" >> longProbList; 
done

in the file there is just 

/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin
/scratch/inputTest/prob/timit.test.pg.list_10_.bin

Upvotes: 4

Views: 120

Answers (2)

John Kugelman
John Kugelman

Reputation: 361675

It thinks your variable name is $i_prob since an underscore is a valid character for a variable name. Use ${i} to fix this:

for i in {1..200}; 
do echo "/scratch/inputTest/prob/timit.test.pg.list_10_${i}_prob.bin" >> longProbList; 
done

Upvotes: 7

therealmarv
therealmarv

Reputation: 3742

You've forgotten the " " around $i

for i in {1..200}; 
do echo "/scratch/inputTest/prob/timit.test.pg.list_10_"$i"_prob.bin" >> longProbList; 
done

Upvotes: 1

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