CODEWITHSUNDEEP
javascript
Pravindra Singh
Pravindra Singh

Reputation: 17

compare 2 arrays based on id as the key and create 2 more arrays out of the comparison

I have 2 arrays (array1 and array2). I want to compare array1 and array2 by using 'id' as the key and want to create 2 resultant arrays out of array2.

  1. First array should contain all the objects which is present in array2 but not in array1.
  2. Second array should contain all the objects which is present in array1 and array2 both, common ones.
const array1 = [{ id: 176770 }, { id: 176771 }, { id: 176820 }];

const array2 = [
    { id: 176770, classfication: "comeone", type: "typeee" },
    { id: 176771, classfication: "comeone1", type: "typeee1" },
    { id: 176820, classfication: "comeone2", type: "typeee2" },
    { id: 176670, classfication: "comeone", type: "typeee" },
    { id: 176761, classfication: "comeone1", type: "typeee1" },
    { id: 176845, classfication: "comeone2", type: "typeee2" },
];

Please help me out to create these 2 arrays.

Upvotes: 0

Views: 116

Answers (1)

Deepak
Deepak

Reputation: 2742

You can loop over the second array and find for an element with same id in first array. If there is no element present in first array, then your first condition is satisfied (Store it in result1). If the element exists in first array, your second condition is satisfied (Store it in result2)

const array1 = [{ "id": 176770 }, { "id": 176771 }, { "id": 176820 }]

const array2 = [{ "id": 176770, "classfication": "comeone", "type": "typeee" }, { "id": 176771, "classfication": "comeone1", "type": "typeee1" }, { "id": 176820, "classfication": "comeone2", "type": "typeee2" }, { "id": 176670, "classfication": "comeone", "type": "typeee" }, { "id": 176761, "classfication": "comeone1", "type": "typeee1" }, { "id": 176845, "classfication": "comeone2", "type": "typeee2" }]

let result1 = []
let result2 = [];

for (let element of array2) {
  let existingInFirst = array1.find(ele => ele.id == element.id);
  if (!existingInFirst) {
    result1.push(element)
  }
  else{
    result2.push(element)
  }
}

console.log(result1)
console.log(result2)

Upvotes: 1

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