CODEWITHSUNDEEP
visual-studio-2010visual-studio-debuggingwatch
odiseh
odiseh

Reputation: 26547

VS2010: Watching variables is not possible?

I use VS2010 as my vb.net compiler but sometimes I cannot watch a local variable while debugging.

Actually, when I add my local variable to watch window, it says that :

'sm' is not declared. It may be inaccessible due to its protection level.

'sm' is my local variable and has beed declared within my routine.

Here is some my simple code snippet:

Public Sub Calculate()
    Dim sm As String        
    Dim c(2) As Byte
    c(0) = 49
    c(1) = 85
    c(2) = 121
    sm = Encrypt_Str(c)
    '...
    '...
End Sub

Well, I cannot watch 'sm' after the line sm = Encrypt_Str(c). What causes this?

Upvotes: 2

Views: 2300

Answers (4)

robnick
robnick

Reputation: 1768

I recently had exactly the same issue in Visual Studio 2013. I was debugging VB.NET code in an ASP.NET code behind class. I could break point, step over and into statements, but trying to view / watch a variable would result in that error:

'myvar' is not declared. It may be inaccessible due to its protection level.

What worked for me was:

  1. Do a clean of the entire solution - so, right click on the solution in the solution explorer window then select Clean Solution.
  2. Rebuild the solution.
  3. Run in debug mode - variable can now be viewed / watched.

Happy coding.

Upvotes: 0

Matthew
Matthew

Reputation: 11

What worked for me was going into the project properties, selecting the 'Debug' tab and then ticking the 'Enable the Visual Studio hosting process' box.

Upvotes: 1

Mike Dole
Mike Dole

Reputation: 687

I couldn't watch any of my controls / variables.. Cleaned and rebuilded but that didn't help either, I created a new configuration in the configuration manager and copied my debug settings et voila my watch worked like a clock again ;)

Regards,

Mike

Upvotes: 0

felknight
felknight

Reputation: 1421

if you are using something like

For Dim i as Intenger To something
  //Do something
Next i

something() //You are debuging here

The variable wount appear on Watch since it just exists for that block of code. But is only a guess. I could be better if you post some code

Upvotes: 0

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