CODEWITHSUNDEEP
pythonpython-3.xdjangodjango-viewsdjango-urls
Sanjay Kapilesh
Sanjay Kapilesh

Reputation: 399

Django Python urlencode same key with multiple values

As the title suggest I am trying to urlencode using Ordered Dict in python

def url_replace(request, field, value, direction=""):
    dict_ = request.GET.copy()
    if field == "order_by" and field in dict_.keys():
        if dict_[field].startswith("-") and dict_[field].lstrip("-") == value:
            dict_[field] = value
        elif dict_[field].lstrip("-") == value:
            dict_[field] = "-" + value
        else:
            dict_[field] = direction + value
    else:
        dict_[field] = direction + str(value)

    print("UNORDERED___________________")
    print(dict_)
    print(super(MultiValueDict, dict_).items())
    print("ORDERED_____________")
    print(OrderedDict(super(MultiValueDict, dict_).items()))
    print(OrderedDict(dict_.items()))
    return urlencode(OrderedDict(dict_.items()))

The output for the above code

UNORDERED___________________
<QueryDict: {'assigned_to_id': ['1', '2'], 'client_id': ['2', '1'], 'page': ['2']}>
dict_items([('assigned_to_id', ['1', '2']), ('client_id', ['2', '1']), ('page', ['2'])])
OrderedDict([('assigned_to_id', '2'), ('client_id', '1'), ('page', '2')])
ORDERED_____________
OrderedDict([('assigned_to_id', ['1', '2']), ('client_id', ['2', '1']), ('page', ['2'])])
OrderedDict([('assigned_to_id', '2'), ('client_id', '1'), ('page', '2')])

As you can see the assigned_to_id has only 2 in the end .

What I am expecting is a ordered dict with

OrderedDict([('assigned_to_id', '2'),('assigned_to_id', '1'), ('client_id', '1'), ('client_id', '2'),('page', '2')])

Maybe there might be a better approach for this, I am a bit new to python

My final aim is to return a dict with multiple keys or anything that can be used in urlencode

Upvotes: 0

Views: 1365

Answers (2)

Kh&#225;nh Ho&#224;ng Dương
Kh&#225;nh Ho&#224;ng Dương

Reputation: 11

Just using urlencode with doseq=True

Note: convert to a dict first, or it will not work

Example:

from urllib.parse import urlencode

@register.filter
def get_query_url(req_get, page_num=None):
    copy = dict(req_get.lists())

    if page_num is not None:
        copy["page"] = page_num

    result = urlencode(copy, doseq=True)
    return f"?{result}"

See - https://docs.python.org/3/library/stdtypes.html#typesmapping

Upvotes: 0

pppig
pppig

Reputation: 1275

urllib.parse.urlencode

When a sequence of two-element tuples is used as the query argument, the first element of each tuple is a key and the second is a value. The value element in itself can be a sequence and in that case, if the optional parameter doseq evaluates to True, individual key=value pairs separated by '&' are generated for each element of the value sequence for the key. The order of parameters in the encoded string will match the order of parameter tuples in the sequence.

Here is a simple example:

from urllib import parse

print(parse.urlencode({"a": [1, 2], "b": 1}, doseq=True))
# "a=1&a=2&b=1"

Upvotes: 3

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