Reputation:
I've seen a lot of examples how to use Data Template Selector to show different controls according to the x:TargetType. I want to create an items control that show a RadioButton, TextBox or TextBlock according to the class tyepe. My class could be like this:
public class MyExample<T>
{
public string Name {get;set;}
public Type Type => TypeOf(T)
public T Value {get;set;}
}
I know that the Xaml can't recognize generics and I don't want to create a markup extension for supporting generics, I want to keep it simple. I don't want to create a concrete class for each type. I know that I can use a Data Trigger to set the content template according to a property (for example type name, or Type Type) but I think that should be an easier way using a Data Template Selector. Can I use the TargetType on the Type Property instead of class type?
Upvotes: 0
Views: 1433
Reputation:
This worked for me:
Window x:Class="WpfApp1.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:local="clr-namespace:WpfApp1" xmlns:syncfusion="http://schemas.syncfusion.com/wpf"
mc:Ignorable="d"
Background="Red"
d:DataContext="{d:DesignInstance local:ViewModel}"
WindowStartupLocation="CenterScreen"
Title="MainWindow" d:Height="100" d:Width="150" Width="300" Height="300">
<Window.Resources>
<Style x:Key="TextBlockStyle" TargetType="TextBlock">
<Setter Property="TextAlignment" Value="Center"/>
</Style>
<DataTemplate x:Key="DefaultTemplate">
<TextBlock Text="{Binding Value}" Style="{StaticResource TextBlockStyle}"/>
</DataTemplate>
<DataTemplate x:Key="NumberTemplate">
<syncfusion:UpDown Name="NumericUpdDown" Value="{Binding Value}"/>
</DataTemplate>
<DataTemplate x:Key="TextTemplate">
<TextBlock Text="{Binding Value}" Style="{StaticResource TextBlockStyle}" />
</DataTemplate>
<DataTemplate x:Key="CheckBoxTemplate">
<CheckBox IsChecked="{Binding Value}" HorizontalAlignment="Center"/>
</DataTemplate>
<DataTemplate x:Key="MyDataTemplate">
<ContentControl Content="{Binding}">
<ContentControl.Style>
<Style TargetType="{x:Type ContentControl}">
<!-- Default Template -->
<Setter Property="ContentTemplate" Value="{StaticResource DefaultTemplate}" />
<!-- Triggers to change Template -->
<Style.Triggers>
<DataTrigger Binding="{Binding Type.Name}" Value="Int32">
<Setter Property="ContentTemplate" Value="{StaticResource NumberTemplate}" />
</DataTrigger>
<DataTrigger Binding="{Binding Type.Name}" Value="String">
<Setter Property="ContentTemplate" Value="{StaticResource TextTemplate}" />
</DataTrigger>
<DataTrigger Binding="{Binding Type.Name}" Value="Boolean">
<Setter Property="ContentTemplate" Value="{StaticResource CheckBoxTemplate}" />
</DataTrigger>
</Style.Triggers>
</Style>
</ContentControl.Style>
</ContentControl>
</DataTemplate>
</Window.Resources>
<ItemsControl
ItemsSource="{Binding Definitions}"
ItemTemplate="{StaticResource MyDataTemplate}">
</ItemsControl>
</Window>
The reason that I don't want concrete type class is avoid adding a lot of code, everytime that I add a new type. What do you think about this solution ?
Upvotes: 1
Reputation: 169400
Can I use the TargetType on the Type Property instead of class type?
No.
The obvious solution would be to create a sub-type and a corresponding DataTemplate
for each type of T
. The implementation for each sub-type would be a one-liner:
public class MyExampleInt : MyExample<int> { }
public class MyExampleString : MyExample<string> { }
If you don't want to create concrete sub-types for whatever reason, you could use a DataTemplateSelector
to select a template based on the type of each MyExample<T>
:
public override DataTemplate SelectTemplate(object item, DependencyObject container)
{
switch (item)
{
case MyExample<int> i:
return IntTemplate;
case MyExample<string> s:
return StringTemplate;
}
return null;
}
Upvotes: 4